Giants among us

[rgtriplec]

Can this list field 1, 2, or 3 giants. The rule sounds like giants take two leaders to field, or does it mean they can get an extra giant for every two leaders?

 

Troop 1

Gronkelfibbets and Mazak

Gonda, Goblin

Goblin Ranger x 20

 

Troop 2

Neek, Goblin

Goblin Warrior x 12

Musician

[Shakandara]

It is definitely not 3, but I could see a case made for it being 2. Hill Giants are normally Unique, meaning you can field only one per list, period. The Noghra doctrine permits you to field 1 for every two leaders you have (i.e. changing the Hill Giant to Non-unique, but only in a very limited way). Where this is a little unclear is that is this in addition to the 1 you could normally field with 1 leader? It does not state so (that the hill giant is in addition), so I'm inclined to say that with anything less than 4 leaders in the list, you can still only field 1 Hill Giant. At 4 leaders, you could take a 2nd; at 6 leaders, a 3rd, and so on.

 

~v

Edited March 6, 2010 by Shakandara

[rgtriplec]

It is definitely not 3, but I could see a case made for it being 2. Hill Giants are normally Unique, meaning you can field only one per list, period. The Noghra doctrine permits you to field 1 for every two leaders you have (i.e. changing the Hill Giant to Non-unique, but only in a very limited way). Where this is a little unclear is that is this in addition to the 1 you could normally field with 1 leader? It does not state so (that the hill giant is in addition), so I'm inclined to say that with anything less than 4 leaders in the list, you can still only field 1 Hill Giant. At 4 leaders, you could take a 2nd; at 6 leaders, a 3rd, and so on.

 

~v

 

That is what I thought but in another thread I saw this list with two. So, I was confused.

[ViciousPanzer]

Yeah I think the list that had 2 troops and 2 hill giants might have been mistaken. The doctrine does seem to indicate that while the Hill Giant does become non unique it still requires a total of 4 troops to use 2 hill giants (well 4 leader led troops). So this would be a legal list it seems:

Reven - 1000 points

 

Troop 1

Gronkelfibbets and Mazak

Goblin Warrior x 15

 

Troop 2

Neek, Goblin

Goblin Warrior x 9

 

Troop 3

Neek, Goblin

Goblin Warrior x 9

 

Troop 4

Neek, Goblin

Goblin Warrior x 9

 

Troop 5

Hill Giant

 

Troop 6

Hill Giant

 

Kinda intersting list actually . . hmmm. But since I'm not the official rules guy I'll leave the official call to someone who is.

 

Joshua

[rgtriplec]

I think it should be one to the first leader, and then the FA ability kicks in. So, 1-1, 3-2, 5-3, 7-4, 9-5...

 

Doesn't seem fair to penalize the first leader by not allowing him to do something all other leaders can do.

[Gus Landt]

I think ya'll are over-thinking it. The rule simply states "1 hill giant may be fielded for every 2 leader-led troops".

 

So if you only have 2 leader-led troops, you only get 1 Hill Giant. You need 4 leader-led troops to get 2 hill giants.

[ViciousPanzer]

Well, what if you only have 1 leader-led troop? Like this:

 

Reven - 999 points

 

Troop 1

Gronkelfibbets and Mazak

Yagun Oog, Ogre Mage

Ombur Skulltooth, Bull Orc

Ogre Warrior x 7

Goblin Warrior x 9

 

Troop 2

Hill Giant

 

Since the FA says "One Hill Giant may be fielded in the Army for every two Leader-led Troops.", this list is illegal if you take the Noghra Doctrine since it contains a Hill Giant but only 1 leader led troop. Not sure this would ever happen (although that does seem like an interesting list heheh).

 

Clearly the intent of the FA is that you can field an additional Hill giant for every two leader led troops or something similar. I don't think preventing a solo troop from choosing one hill giant was the original intent but I could be wrong. Has happened before lol.

 

As far as how many you can take with 4 troops, yeah I think Gus explained it pretty well. 2 troops = 1 hill giant, 3 troops = 1 hill giant, 4 troops = 2 hill giants, etc.

 

Joshua

[rgtriplec]

Gronkelfibbets and Mazak

Gonda, Goblin

Goblin Ranger x 20

 

 

Neek, Goblin

Goblin Warrior x 12

Musician

 

Hill Giant

 

Hill Giant

 

So, this rule has no bearing on the normal taking of one unique giant. So, the list is legal, your one unique giant, + your nohgra doctrine giant?

[Shakandara]

I think that the intent is that it has no bearing on the first giant, but that doesn't mean it grants you the ability to take a 2nd one at only 2 leaders. For that, as Gus has already pointed out, you have to wait until Leader-led troop #4 before you can take the 2nd giant. I can certainly see where you are coming from, and the wording is a bit fuzzy. It should have probably read something like, "for every two leader-led troops past the first 2, can take 1 additional hill giant as a solo choice."

 

~v

Edited March 7, 2010 by Shakandara

[rgtriplec]

I think that the intent is that it has no bearing on the first giant, but that doesn't mean it grants you the ability to take a 2nd one at only 2 leaders. For that, as Gus has already pointed out, you have to wait until Leader-led troop #4 before you can take the 2nd giant. I can certainly see where you are coming from, and the wording is a bit fuzzy. It should have probably read something like, "for every two leader-led troops past the first 2, can take 1 additional hill giant as a solo choice."

 

~v

 

Gotcha.